The Common-Emitter Amplifier Circuit (Experiment 6 - Part1)

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Published 2021-04-07
Text book: Electronic Devices, Thomas Floyd
Lab Book: Laboratory Exercises for Electronic Devices

All Comments (21)
  • @kapsabet3
    Very patient teacher Love it thanks.
  • @manaapei1942
    I love this video. Thank you so much, it really helped❤️
  • @user-cd1kr1ry3d
    Thank you soooo much, you help me a lot with my lab report❤
  • @arafathj2144
    Hands off teacher what a brilliant class😘😘
  • @RexxSchneider
    For those who want to check their calculations of the computed values, here are the answers, assuming β=200 and Vbe=0.65V: Vb = 3.72V Ve = 3.07V Ie = Ic = 7.1mA Vc = 4.89V Vce = 1.82V AC voltage gain (no load) = 9.7 -- with 10K load, Av = 8.8 Input impedance = 2.8K -3dB frequency for bypass capacitor = 33Hz -3dB frequency for input capacitor = 57Hz Note that with a loaded gain of 8.8 and an input signal of 300mVpp, the output will be 2.64Vpp, which is getting close to the available output swing of 2x(Vce-Vce(sat)) = 2 x (1.82-0.2) = 3.2Vpp.
  • @AF-ge4pe
    Thank you ma'am this helped me a lot!
  • Thank you❤❤❤Your explanation really helped me a lot ya rab td5oly el gana❤
  • @user-kv8hs5eb7i
    00:02 Understanding the layout of a breadboard for the common emitter amplifier circuit 02:34 To connect the transistor in the circuit, match the curved side of the transistor symbol with the curved side of the symbol on the schematic. 05:09 Connecting components in the common-emitter amplifier circuit 07:49 Connecting components in a common-emitter amplifier circuit 10:36 Connect the capacitor leg on number 55 to the collector 13:35 Connecting components to the ground simplifies circuit connections. 16:14 Connect the ground and positive sides of the circuit to the appropriate components. 18:33 Connect the one microfarad capacitor to the base 20:56 Calculating emitter voltage (Ve) and collector-emitter voltage (Vce)
  • Good lecture madam, but the visibility of the circuit diagram needs some improvements. 🙏🙏